Evaluate lim x/|x| x-->0

1 answer

x/|x| is -1 below 0 and 1 above zero.

Since it is discontinuous at x = 0, there is no limit.

Similar Questions

i need some serious help with limits in pre-calc.here are a few questions that i really do not understand. 1. Evaluate: lim

Top answer: Seizing the means of production Read more.
5) Use the L’Hopital’s method to evaluate the following limits. In each case, indicate what type of limit it is ( 0/0,

Top answer: sin(x^2-4)/(x-2) --> 2xcos(x^2-4)/1 --> 4 ln(x-3)/(x-5) --> (1/(x-3))/5 -> 0 (x-pi/4)tan(2x) = Read more.
How do we evaluate limit of,lim x-> 0 [ln(x+1)/( (2^x) - 1)] I tried using the substitution x+1 = e^k , when x tends to 0 so

Top answer: How about good old L'Hopital's rule lim x-> 0 [ln(x+1)/( (2^x) - 1)] = lim x-> 0 [1/(x+1) / Read more.
Given that lim x->c f(x)=6 and that lim x->c g(x)= -4, evaluate the following limit. Assume that c is a constant. The x in front

Top answer: The x in front of the f is any constant you would put in the equation. Example: x->5 5=c lim [xf(x) Read more.
Evaluate each of the following.(a) lim x->0(e^x)-1-x/ x^2 (b) lim x->0 x-sinx/x^3 (c) lim x->infinity (In x)^2/x (d) lim x->0+

Top answer: b.lim 1-1/3cosx^2 Read more.
Given that lim x-> f(x)=6 and that lim x-> g(x)= -4, evaluate the following limit. Assume that c is a constant.lim -2f(x) - 12 /

Top answer: I have to tell you , your notation is bizzare. What is x approaching? infinity? Your work seems ok, Read more.
Lim sin2h sin3h / h^2h-->0 how would you do this ?? i got 6 as the answer, just want to make sure it's right. and i couldn't get

Top answer: the first one is correct. Here is a simple way to check your limit answers if you have a calculator Read more.
need to find:lim as x -> 0 of 4(e^2x - 1) / (e^x -1) Try splitting the limit for the numerator and denominator lim lim x->0

Top answer: To solve this limit, start by splitting the limit for the numerator and denominator separately. lim Read more.
Evaluate each limit. If it exists.a) Lim x^3 + 1 x->1 ------- x + 1 b) Lim 3x^2 - x^3 x->0 ---------- x^3 + 4x^2 c) Lim 16 - x

Top answer: do you mean x --> -1? Otherwise, there's no problem evaluating the fraction. x^3+1 = (x+1)(x^2-x+1) Read more.
Find the following limits algebraically or explain why they don’t exist.lim x->0 sin5x/2x lim x->0 1-cosx/x lim x->7 |x-7|/x-7

Top answer: a lot of your questions contain ambiguous typing e.g. the second last one probably says lim ( Read more.