A diver running 1.69 m/s dives out horizontally from the edge of a vertical cliff and 3.11 s later reaches the water below. How high was the cliff, and how far from the base did the diver hit the water?
h = .5 g t^2
h= .49 (3.11)^2
d = 1.69 t
h= .49 (3.11)^2
d = 1.69 t