The play sold 88 tickets. The adult tickets sold for $8 and the kid tickets sold for $5. The total amount collect for tickets was $614. How many tickets of each type were sold?
adult tickets --- x
child tickets --- 88-x
8x + 5(88-x) = 614
solve for x, etc.
Adult tickets=x
Child tickets=88-x
8x + 5(88-x)=614
8x + 440-5x=614
3x=614-440
3x=174
x=58
Adult=58
child=30
If someone paid $95 for ten tickets to a concert. Adult tickets cost $15 each. Kids tickets cost $8 each. How many of each kind of tickets did they buy?
To determine how many adult and kid tickets were sold, we can use a system of equations approach.
Let's assume the number of adult tickets sold is x, and the number of kid tickets sold is y.
According to the given information, we know that:
1. The total number of tickets sold is 88: x + y = 88
2. The total amount collected from ticket sales is $614: 8x + 5y = 614
To solve this system of equations, we can use the substitution or elimination method.
Let's use the substitution method:
From equation 1, we can express x in terms of y: x = 88 - y
Substituting this value of x into equation 2, we get:
8(88 - y) + 5y = 614
Expanding the equation:
704 - 8y + 5y = 614
Combining like terms:
-3y = 614 - 704
-3y = -90
Dividing both sides by -3:
y = -90 / -3
y = 30
Now, we can substitute the value of y back into equation 1 to find x:
x + 30 = 88
x = 88 - 30
x = 58
Therefore, 58 adult tickets and 30 kid tickets were sold.