Using a special balloon that is permeable to water but not sucrose to make an "artificial" cell. The balloon is filled with a solution of 20% sucrose and 80% water and is immersed in a beaker containing a solution of 40% sucrose and 60% water. The solution in the balloon is ?
To determine the solution in the balloon, we need to understand osmosis and the concept of concentration gradients.
Osmosis is the movement of water molecules across a semipermeable membrane, from a region of lower solute concentration to a region of higher solute concentration. In this case, the semipermeable membrane is the special balloon that is permeable to water but not sucrose.
In your setup, the balloon is filled with a solution of 20% sucrose and 80% water. It is then immersed in a beaker containing a solution of 40% sucrose and 60% water. The solute in this case is sucrose, and the solvent is water.
Since the solution inside the balloon has a lower concentration of sucrose (20%) compared to the solution in the beaker (40%), the water will tend to move out of the balloon and into the beaker through osmosis. This occurs because the higher concentration of sucrose in the beaker creates a concentration gradient.
As a result, water will leave the balloon, and sucrose from the beaker will not be able to pass through the balloon membrane. This means that the concentration of sucrose inside the balloon will remain the same, at 20%, while the concentration of water will decrease.
Therefore, the solution in the balloon remains 20% sucrose and 80% water.