Two group of male students cost their past on a particular proposal.the result are as follows: Group infavour against A 128 32 B 96 48 <a> if a student in favour of proposal is selected for a post. What is the probability that he is from group A ? if a student is chosen at random, what is the probability that he is against proposal.
Nuts to this, it makes no sense.
What does "cost their past" mean?
If you mean
group A in favor: 128
group A opposed: 32
group B in favor: 96
group B opposed: 48
Now if all those infavor (128+96), if one is selected, Pr(A)=128/(128+96)
If a student is chosen at random,
Pr(against)=totalagainst/total students
= (32+48)/(128+32+96+48)
I am also confused by what "in favour against" means.
To find the probabilities, we need to use the total number of students in each group:
Group A: 128 students in favor + 32 students against = 160 students
Group B: 96 students in favor + 48 students against = 144 students
a) The probability that a student in favor of the proposal is selected from Group A can be calculated as the number of students in favor from Group A divided by the total number of students in favor:
Probability = Number of students in favor from Group A / Total number of students in favor
= 128 / (128 + 96)
= 128 / 224
= 0.5714 (rounded to four decimal places)
So, the probability that a student in favor of the proposal is selected from Group A is approximately 0.5714.
b) The probability that a student chosen at random is against the proposal can be calculated as the number of students against the proposal divided by the total number of students:
Probability = Number of students against the proposal / Total number of students
= (32 + 48) / (160 + 144)
= 80 / 304
= 0.2632 (rounded to four decimal places)
So, the probability that a student chosen at random is against the proposal is approximately 0.2632.