Determine the mass of CuSO4.5H20 needed to make 100.00mL of a .100M CuSO4.5H20 aqueous solution..
.100M solution has .100 mol/L
You only want 100mL, so you only need .01mol
just multiply the molecular mass of the compound by .01 to get the mass in g.
0.05
To determine the mass of CuSO4.5H20 needed to make 100.00 mL of a 0.100 M CuSO4.5H20 aqueous solution, you will need to use the molarity formula and the molar mass of CuSO4.5H20.
First, let's break down the given information:
- Volume of solution: 100.00 mL
- Molarity of the solution: 0.100 M
The molarity formula is given by:
Molarity (M) = moles of solute / volume of solution (in liters)
We need to rearrange this formula to solve for the moles of solute.
moles of solute = Molarity × volume of solution (in liters)
Since we have the molar mass of CuSO4.5H20, we can convert the moles of solute into grams using the formula:
moles of solute = mass of solute / molar mass
Now, let's calculate the moles of CuSO4.5H20 using the given information:
Moles of CuSO4.5H20 = Molarity × volume of solution (in liters)
= 0.100 M × 100.00 mL / 1000 mL/L (converting mL to L)
= 0.010 mol
Finally, to determine the mass of CuSO4.5H20, we'll use the molar mass of CuSO4.5H20. The molar mass of CuSO4.5H20 can be calculated by summing up the molar masses of its constituent atoms.
The molar mass of CuSO4.5H20 can be calculated as follows:
- The atomic mass of Cu = 63.55 g/mol
- The atomic mass of S = 32.07 g/mol
- The atomic mass of O (4 atoms in CuSO4) = 16.00 g/mol
- The atomic mass of H (10 atoms in 5H2O) = 1.01 g/mol
- The atomic mass of O (5 atoms in 5H2O) = 16.00 g/mol
To calculate the molar mass of CuSO4.5H20:
Molar mass = (63.55 g/mol) + (32.07 g/mol) + (16.00 g/mol × 4) + (1.01 g/mol × 10) + (16.00 g/mol × 5)
= 249.68 g/mol
Now, let's calculate the mass of CuSO4.5H20:
Mass of CuSO4.5H20 = moles of CuSO4.5H20 × molar mass
= 0.010 mol × 249.68 g/mol
= 2.50 g
Therefore, you will need 2.50 grams of CuSO4.5H20 to make 100.00 mL of a 0.100 M CuSO4.5H20 aqueous solution.