A 5 gram sample of a hydrate of BaCL2 was heated, and only 4.3g of the anhydrous salt remained. What percentage of water was in the hydrate?
14%
How much water water was evolved? That is 5g - 4.3 g = 0.7g
%H2O = (0.7/5)*100 = ?
Well, it looks like BaCL2 got all hot and bothered and lost some water along the way! To find out the percentage of water in the hydrate, we can start by determining the mass of water that was lost.
The mass of the water that was lost can be found by subtracting the mass of the anhydrous salt (4.3g) from the initial mass of the hydrate (5g). So, 5g - 4.3g = 0.7g of water was lost.
Now, to determine the percentage of water, we divide the mass of water lost (0.7g) by the initial mass of the hydrate (5g) and then multiply by 100.
(0.7g / 5g) x 100 = 14%
So, approximately 14% of the hydrate was made up of water. Talk about a dry situation!
To find the percentage of water in the hydrate, we need to determine the mass of water lost during the heating process.
Step 1: Calculate the mass of water lost
Mass of water lost = Mass of starting sample - Mass of anhydrous salt
Mass of water lost = 5 g - 4.3 g
Mass of water lost = 0.7 g
Step 2: Calculate the percentage of water lost
Percentage of water lost = (Mass of water lost / Mass of starting sample) × 100%
Percentage of water lost = (0.7 g / 5 g) × 100%
Percentage of water lost = 14%
Therefore, the percentage of water in the hydrate is 14%.
To find the percentage of water in the hydrate, we need to calculate the amount of water that was lost during the heating process.
First, we need to find the amount of anhydrous salt remaining. The mass of the anhydrous salt is given as 4.3g.
Next, let's calculate the amount of water that was lost. The initial mass of the sample is given as 5g. Therefore, the mass of water lost can be calculated as follows:
Mass of water lost = Initial mass of the sample - Mass of anhydrous salt remaining
= 5g - 4.3g
= 0.7g
Finally, we can calculate the percentage of water in the hydrate using the formula:
Percentage of water in the hydrate = (Mass of water lost / Initial mass of the sample) * 100
Plugging in the values we found:
Percentage of water in the hydrate = (0.7g / 5g) * 100
= 14%
Therefore, the percentage of water in the hydrate is 14%.