An elevator (mass 4175 kg) is to be designed so that the maximum acceleration is 0.0700g.

What is the maximum force the motor should exert on the supporting cable?

force=mass*a=mass(1.0700)9.8

To find the maximum force the motor should exert on the supporting cable, we need to calculate the maximum acceleration first.

Given:
Mass of the elevator (m) = 4175 kg
Maximum acceleration (a) = 0.0700g

First, let's convert g, which is the acceleration due to gravity, into m/s^2. The standard value of acceleration due to gravity is approximately 9.8 m/s^2.

g = 9.8 m/s^2

So, the maximum acceleration can be calculated as:

a = 0.0700 * 9.8 m/s^2

Now, we can calculate the maximum acceleration:

a = 0.686 m/s^2

The force (F) exerted on an object can be calculated using Newton's second law of motion:

F = m * a

where:
F = force exerted on the object (in Newtons)
m = mass of the object (in kilograms)
a = acceleration of the object (in meters per second squared)

Now, we can substitute the values and calculate the maximum force:

F = 4175 kg * 0.686 m/s^2

F = 2861.75 N (rounded to the nearest whole number)

Therefore, the maximum force the motor should exert on the supporting cable is approximately 2862 Newtons.