I keep getting wrong answer for this question.
Write as a single logarithm
log(x+1)+2log(2x+1)-log(x-3)
2log(2x+1) is the same as log(2x+1)^2
Now you have:
log(x+1) + log(2x+1)^2 - log(x-3)
Does that help?
Write as a single logarithm
log(x+1)+2log(2x+1)-log(x-3)
Now you have:
log(x+1) + log(2x+1)^2 - log(x-3)
Does that help?