Question

2y^2 -8y -3 = 0

please solve

Answer 1

Since this equation does not factor easily, use the quadratic formula to solve for x.

x = [-b + or - √(b^2 - 4ac)]/2a

a = 2, b = -8, and c = -3

Substitute the values and solve for x.

I'll let you take it from here.