The figure shows the treatment of fractures of the humerus shaft with a cast of the upper arm bent by 100 to 110 degrees at the elbow joint, and an attached traction device. The traction device keeps the upper arm under tension to lower the risk of fracture dislocation due to muscle contraction. What mass must be used for the traction device if the muscle force it must compensate is 7.5 N?
I would need to see the Figure to understand and answer this question.
There is no given figure, you have to draw it from the question.
"The figure shows.." would seem to imply otherwise.
0.7 is the answers
0.7 is one answer.
To determine the mass needed for the traction device, we need to understand the forces involved and apply Newton's second law of motion.
According to the given information, the muscle force that the traction device must compensate for is 7.5 N. This force is acting in the opposite direction to the muscle contraction to prevent fracture dislocation.
Newton's second law states that force (F) is equal to the mass (m) multiplied by the acceleration (a). In this case, the acceleration is due to gravity, which is approximately 9.8 m/s^2.
So, to calculate the mass required for the traction device, we can rearrange the equation as follows:
F = m * a
m = F / a
Plugging in the values:
m = 7.5 N / 9.8 m/s^2
m ≈ 0.77 kg
Therefore, the mass required for the traction device would be approximately 0.77 kg to compensate for a muscle force of 7.5 N.