# Trig

Solve the following trig equation

2cos(x-π/6)=1

1. 2cos(x-π/6) = 1
let y = (x-π/6)
cos(y) = 1/2
y = π/3, -π/3
substituting back the value of y,
(x - π/6) = π/3
x = π/2

(x - π/6) = -π/3
x = -π/6 or 11π/12

hope this helps~ :)

posted by Jai

First Name

## Similar Questions

1. ### calculus

1. what trig function has an amplitue of 1 and negative values for angles between π/2 and π? 2. what trig function never crosses the x-axis and has a value of 2 at π/6? are these correct? 3. what trig function has a
2. ### Trig

Solve the trig equation exactly over the indicated interval. tanθ = 0, all real numbers I know the answer is πn, but I don't understand how they got this. I get that tanθ = 0 on π and 2π on the unit
3. ### Trig

find all solutions to the equation √3 csc(2theta)=-2 Would the answer be π/6 + 2πn, 5π/6 +2πn or π/6 + πn, 5π/6 +πn? or neither?
4. ### Solving Trig equation

Solve the trig equation exactly in the interval 0≤x≤2π. tan x + tan π/3 ------------------ = square root 3 1 - tan x tan π/3
5. ### math (final trig problem)

Solve for x on the interval [0,π/2): cos^3(2x) + 3cos^2(2x) + 3cos(2x) = 4 I havent done trig for a while so what exactly does that mean in solving for x on that interval and how would i go about doing that? Where are you
6. ### trig

Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0