Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by
S(t) = 68 - 20 log (t+1), t > 0
There is no question here. There is just an equation.
11. Students in an accounting class took a final exam and then took equivalent forms of the exam at monthly intervals thereafter. The average score
as a percent, after t months was given by
To find the average score of the students after a given number of months, you can use the formula:
S(t) = 68 - 20 log (t+1)
Here's how you can calculate the average score at a specific time:
1. Determine the number of months, t, for which you want to calculate the average score.
For example, if you want to calculate the average score after 3 months, the value of t would be 3.
2. Substitute the value of t into the formula.
S(t) = 68 - 20 log (t+1)
S(3) = 68 - 20 log (3+1)
3. Simplify the expression inside the logarithm.
S(3) = 68 - 20 log (4)
4. Use the logarithm rules to evaluate the logarithm.
S(3) = 68 - 20 log 4
S(3) = 68 - 20 * log(10) / log(4)
5. Calculate the logarithm values using a calculator.
Find the logarithm of 10: log(10) ≈ 1
Find the logarithm of 4: log(4) ≈ 0.602
6. Substitute the values back into the equation.
S(3) = 68 - 20 * 1 / 0.602
S(3) ≈ 31.99
So, the average score after 3 months would be approximately 31.99 percent.