What is the balanced equation for oxidation of iodide ion by oxygen (O2) that occurs which produces iodine.
4I^-(aq) + O2(g) 4H^+ ==> 2I2 + 2H2O
I^- goes to I2.
Probably O2 goes to H2O or OH^-
Thank you DrBob222
To determine the balanced equation for the oxidation of iodide ion (I-) by oxygen (O2) to produce iodine (I2), we need to follow a step-by-step process:
Step 1: Write the half-reactions.
The oxidation of iodide ion (I-) can be represented by the following half-reaction:
I- -> I2
The reduction of oxygen (O2) can be represented by the following half-reaction:
O2 + 4e- -> 2O2-
Step 2: Balance the number of electrons.
Since the oxidation half-reaction (I-) involves a change of two electrons, we need to balance the number of electrons in the reduction half-reaction (O2). To do this, we multiply the oxidation half-reaction by 2:
2I- -> I2
The balanced reduction half-reaction remains the same:
O2 + 4e- -> 2O2-
Step 3: Add the half-reactions together.
Now we can combine the two half-reactions to obtain the balanced equation:
2I- + O2 + 4e- -> I2 + 2O2-
However, this equation is not yet fully balanced. To complete the balancing process, we need to make sure both sides of the equation have the same number of atoms of each element.
Step 4: Balance atoms other than oxygen and hydrogen.
In the equation, there are two iodine atoms on the right side and only one on the left side. To balance the iodine atoms, we need to multiply the oxidation half-reaction by 2:
4I- + O2 + 8e- -> 2I2 + 4O2-
Now, the number of iodine atoms is balanced.
Step 5: Balance the oxygen atoms using water molecules and the hydrogen atoms using hydrogen ions (H+).
On the left side, there are eight oxygen atoms from the oxygen molecule (O2), while on the right side, there are four oxygen atoms from the iodine molecules (I2) and four oxygen atoms from the water molecule (H2O). To balance the oxygen atoms, we need to add four water molecules (H2O) to the left side:
4I- + O2 + 8e- + 4H2O -> 2I2 + 4O2- + 8OH-
Finally, balance the hydrogen atoms by adding eight hydrogen ions (H+) to the right side:
4I- + O2 + 8e- + 4H2O -> 2I2 + 4O2- + 8OH- + 8H+
This is the balanced equation for the oxidation of iodide ion by oxygen that produces iodine:
4I- + O2 + 4H2O -> 2I2 + 4O2- + 8OH- + 8H+