If the score on a test has a mean of 52 and a standard deviation of 5, what is the z-score for a score of 58
Z = (score-mean)/SD
Insert values and solve.
To find the z-score for a score of 58, we can use the formula:
z = (x - μ) / σ
Where:
- z is the z-score
- x is the given score
- μ is the mean of the distribution
- σ is the standard deviation
In this case, the given score is 58, the mean is 52, and the standard deviation is 5. Plugging these values into the formula, we get:
z = (58 - 52) / 5
Simplifying this calculation, we have:
z = 6 / 5
Therefore, the z-score for a score of 58 is 1.2.