Balance the word equation solid calcium carbonate reacts with hydrochloric acid to yield aqueous calcium chloride, carbon dioxide gas, and liquid water?
CaCO3(s) + 2HCl(aq) ==> CaCl2(aq) + H2O(l) + CO2(g)
Ca=1
C=1
O=3
H=2
Cl=2
Ca=1
C=1
O=3
H=2
Cl=2
To balance the given word equation:
Solid calcium carbonate (CaCO3) + Hydrochloric acid (HCl) → Aqueous calcium chloride (CaCl2) + Carbon dioxide gas (CO2) + Liquid water (H2O)
Step 1: Count the number of atoms on each side of the equation.
On the left-hand side (reactants):
1 Calcium (Ca)
1 Carbon (C)
3 Oxygen (O)
1 Hydrogen (H)
1 Chlorine (Cl)
On the right-hand side (products):
1 Calcium (Ca)
2 Chlorine (Cl)
1 Carbon (C)
3 Oxygen (O)
2 Hydrogen (H)
Step 2: Balance the elements one by one.
Counting calcium (Ca) atoms:
There is already 1 Ca atom on both sides, so it is balanced.
Counting carbon (C) atoms:
There is already 1 C atom on both sides, so it is balanced.
Counting oxygen (O) atoms:
There are 3 O atoms on the left, and 3 O atoms on the right, so they are balanced.
Counting hydrogen (H) atoms:
There is 1 H atom on the left, and 2 H atoms on the right. To balance this, we need to double the coefficient of hydrochloric acid.
Solid calcium carbonate + 2 Hydrochloric acid → Calcium chloride + Carbon dioxide + Water
Counting chlorine (Cl) atoms:
There is 1 Cl atom on the left, and 2 Cl atoms on the right. To balance this, we need to double the coefficient of calcium chloride.
Solid calcium carbonate + 2 Hydrochloric acid → 2 Calcium chloride + Carbon dioxide + Water
Step 3: Verify that all elements are now balanced.
On the left-hand side:
1 Calcium (Ca)
1 Carbon (C)
3 Oxygen (O)
2 Hydrogen (H)
2 Chlorine (Cl)
On the right-hand side:
2 Calcium (Ca)
2 Chlorine (Cl)
1 Carbon (C)
3 Oxygen (O)
2 Hydrogen (H)
All elements are now balanced, and the balanced equation is:
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
To balance the word equation: solid calcium carbonate reacts with hydrochloric acid to yield aqueous calcium chloride, carbon dioxide gas, and liquid water, we need to make sure that the number of atoms of each element is equal on both sides of the equation.
Let's break down the equation and balance it step by step.
1. Write down the unbalanced equation:
CaCO3 + HCl → CaCl2 + CO2 + H2O
2. Start by balancing the calcium (Ca) atoms. In this equation, there is one calcium atom on the left side and one on the right side. It is already balanced.
CaCO3 + HCl → CaCl2 + CO2 + H2O
3. Next, balance the chlorine (Cl) atoms. On the left side, there is one chlorine atom from HCl, and on the right side, there are two chlorine atoms from CaCl2. To balance this, we need to place a coefficient of 2 in front of HCl.
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
4. Now, let's balance the carbon (C) atoms. There is one carbon atom in CaCO3 on the left side and one carbon atom in CO2 on the right side. Carbon is already balanced.
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
5. Lastly, balance the hydrogen (H) atoms. On the left side, there are two hydrogen atoms from 2HCl, and on the right side, there are two hydrogen atoms from H2O. Hydrogen is already balanced.
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
Now, the equation is balanced, and it correctly represents the reaction: solid calcium carbonate reacts with hydrochloric acid to yield aqueous calcium chloride, carbon dioxide gas, and liquid water.