An object with a charge of -4.5 micro C and a mass of 1.1×10−2 kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight.

A) Find the magnitude of the electric field.

B)Find the direction of the electric field.

upward
downward
to the left
to the right
C)If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.

D)If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.

upward
downward
to the left
to the right

A) To find the magnitude of the electric field, we can set up an equation equating the electric force to the weight of the object.

The electric force experienced by the object is given by Equation 1:
Electric force = q * E,
where q is the charge of the object and E is the electric field.

The weight of the object is given by Equation 2:
Weight = m * g,
where m is the mass of the object and g is the acceleration due to gravity.

Since the electric force equals the weight, we can set Equation 1 equal to Equation 2:
q * E = m * g.

To find the magnitude of the electric field E, we rearrange the equation to solve for E:
E = (m * g) / q.

Substituting in the given values:
Charge, q = -4.5 micro C = -4.5 x 10^-6 C.
Mass, m = 1.1 x 10^-2 kg.
Acceleration due to gravity, g = 9.8 m/s^2.

Plugging these values into the equation, we get:
E = (1.1 x 10^-2 kg * 9.8 m/s^2) / -4.5 x 10^-6 C.

Calculating the magnitude of the electric field gives us the answer to part A.

B) To find the direction of the electric field, we need to consider the sign of the charge. Since the object experiences an upward force equal to its weight, we can conclude that the charge on the object must be negative.

Negative charges experience a force opposite to the direction of the electric field. Therefore, the direction of the electric field is downward.

C) If the electric charge on the object is doubled while its mass remains the same, the equation for the acceleration (a) of the object is given by:
a = (q * E) / m,
where q is the charge, E is the electric field, and m is the mass.

Since the charge is doubled, the new charge (q') is -2 * 4.5 x 10^-6 C = -9.0 x 10^-6 C.

We can assume that the electric field (E) remains the same because it is determined by external factors, such as the source of the electric field.

Substituting the new charge (q') and the given mass (m) into the equation, we can solve for the direction and magnitude of the acceleration.

D) The given direction options for acceleration (upward, downward, to the left, to the right) are not enough to determine the actual direction of acceleration.

The direction of the acceleration depends on the direction of the electric field. Since the problem does not provide any additional information about the direction of the electric field, we cannot determine the direction of acceleration.