For one pony, thecritical force was 1.16 times its body weight. It experienced a force of 0.75 times its body weight at a speed of 2 meters per second, and a force of 0.93 times its body weight at 3 meters per second. At what speed did the pony switch from a trot to a gallop?

I know the answer is 4.3 but I want to know how :/ someone pls help.

To find the speed at which the pony switched from a trot to a gallop, we need to find the point where the force exerted on the pony exceeded the critical force of 1.16 times its body weight.

We are given that at a speed of 2 meters per second, the force exerted on the pony is 0.75 times its body weight, and at a speed of 3 meters per second, the force exerted is 0.93 times its body weight.

Let's assume the switch from a trot to a gallop occurs at a speed of x meters per second. At this speed, the force exerted on the pony will be greater than or equal to the critical force, which is 1.16 times its body weight.

So, we have the following equation:
x * (0.93 - 0.75) + 0.75 = 1.16

Simplifying the equation, we get:
x * 0.18 + 0.75 = 1.16
x * 0.18 = 1.16 - 0.75
x * 0.18 = 0.41
x = 0.41 / 0.18
x ≈ 2.28

Therefore, the switch from a trot to a gallop occurs at a speed of approximately 2.28 meters per second.

However, if the provided answer is 4.3 meters per second, it suggests that there might be additional information or a different calculation involved. Please double-check the given problem statement or consult the source of the answer for further clarification.