What is the balanced equation for the reaction between sodium tetraborate and sulfuric acid?

Na2B4O7 + H2SO4 + 5H2O ==>4H3BO3 + Na2SO4

To determine the balanced equation for the reaction between sodium tetraborate (Na2B4O7) and sulfuric acid (H2SO4), we need to follow these steps:

Step 1: Write the chemical formulas for the reactants and products:
Sodium tetraborate: Na2B4O7
Sulfuric acid: H2SO4

Step 2: Determine the products of the reaction by analyzing the elements involved.
Sodium tetraborate contains sodium (Na), boron (B), and oxygen (O). Sulfuric acid contains hydrogen (H), sulfur (S), and oxygen (O).

Step 3: The reaction between these chemicals will result in the formation of water (H2O), sodium sulfate (Na2SO4), and boric acid (H3BO3).

Step 4: Write the balanced equation by ensuring that the number of atoms on each side of the equation is the same.

The balanced equation for the reaction is:
Na2B4O7 + 4 H2SO4 → 2 Na2SO4 + H3BO3 + 4 H2O

In this equation, both sides have the same number of atoms for each element, indicating that the reaction is properly balanced.