A 0.75 kg mass of copper changes temperature from 145.0 C to 46.0 C. How much heat was exchanged in Joules? Did the heat flow into the copper or out of the copper?
Q = .75 * specific heat of copper* (145-46)
the copper lost heat to get cooler !
so you just multiply those all together?
Yes. Look up the specific heat capacity for copper in Joules/ Kg deg K in your text
thanks
To calculate the amount of heat exchanged in this scenario, we can use the formula:
Q = mcΔT
Where:
Q = heat exchanged (in Joules)
m = mass of the object (in kg)
c = specific heat capacity of the material (in J/kg·C)
ΔT = change in temperature (in C)
Given:
m = 0.75 kg
c (specific heat capacity of copper) = 387 J/kg·C (approximately)
ΔT = (46.0 C) - (145.0 C) = -99.0 C
Now we can substitute the values into the formula and calculate the heat exchanged:
Q = (0.75 kg) * (387 J/kg·C) * (-99.0 C)
Calculating this gives us:
Q = -29,236.25 J
The negative sign indicates that heat flowed out of the copper during the temperature change.
Therefore, approximately 29,236.25 J of heat was exchanged, and it flowed out of the copper.