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An aqueous solution of calcium chloride boils at 101.3. How many kilograms of calcium chloride were dissolved in 1000 g of the solvent?

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asked by Nita
  1. CaCl2 is three particles per molecule.

    deltaTemp=1.3=.52*molality

    solve for molality, then

    molality= moles/1000 solve for moles, then finally,grams of CaCl2 from moles, then divide by 1000 to get kg

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