A 15 kg mass, moving east at 5 m/s, collides elastically with another 10 kg mass, moving west at 1 m/s. After the collision, the larger mass moves off with a velocity of 3 m/s. What is the final velocity of the smaller mass?
Is it 4m/s? Or would it be 2m/s?
Do you add the momentum of the 2 masses because of conservation of momentum or subtract them because they're going in different directions?
conservation of energy.
energy before= energy after
15*5^2+10*1^2=15*3^2+10*v^2
V^2= 1.5*25+1-1.5*9
v= 5m/s check the math.
A solenoid has a cross-sectional area of 5.80 10-4 m2, consists of 100 turns per meter, and carries a current of 0.6 A. A 10 turn coil is wrapped tightly around the circumference of the solenoid. The ends of the coil are connected to a 0.7 resistor. Suddenly, a switch is opened, and the current in the solenoid dies to zero in a time of 0.16 s. Find the average current induced in the coil.
What is the momentum of a car travelling at 65 m per second with a mass of 95,000 kg
To find the final velocity of the smaller mass after the collision, we can use the principles of conservation of momentum and apply them to the situation.
First, let's write down the initial and final momentum equations for the system:
Initial momentum: (mass1)(velocity1) + (mass2)(velocity2) = (15 kg)(5 m/s) + (10 kg)(-1 m/s)
Final momentum: (mass1)(final velocity1) + (mass2)(final velocity2) = (15 kg)(3 m/s) + (10 kg)(? m/s) - assuming the final velocity of the smaller mass is "?".
Now, since the collision is elastic, which means there is no loss of kinetic energy, we can apply the principle of conservation of momentum. According to this principle, the total momentum of an isolated system before and after a collision remains constant.
Therefore, we can set the initial momentum equal to the final momentum and solve for the final velocity of the smaller mass:
(15 kg)(5 m/s) + (10 kg)(-1 m/s) = (15 kg)(3 m/s) + (10 kg)(? m/s)
Now, let's solve for "?":
75 kg*m/s - 10 kg*m/s = 45 kg*m/s + 10 kg*m/s
65 kg*m/s = 55 kg*m/s + 10 kg*m/s
65 kg*m/s = 65 kg*m/s
Thus, the equations are balanced, and it means that the final velocity of the smaller mass is indeed 2 m/s.
In summary, when applying the principle of conservation of momentum, we add the momenta of the two masses together (considering the direction of the motion) to reach the final momentum equation.