How long would it take for a ball dropped from the top of a 400 foot building to hit the ground? Round your answer to two decimal places
Use gravity formula
5sec
To find the time it takes for a ball to drop from the top of a building, we can use the formula for the time of free fall:
t = √(2h/g)
Where:
t = time (in seconds)
h = height (in feet)
g = acceleration due to gravity (approximately 32.2 ft/s^2)
In this case, the height of the building is 400 feet and the acceleration due to gravity is 32.2 ft/s^2.
Plugging these values into the formula, we get:
t = √(2*400/32.2)
Simplifying this equation, we have:
t = √(800/32.2)
t = √24.84
t ≈ 4.98 seconds
Therefore, it would take approximately 4.98 seconds for the ball to hit the ground when dropped from the top of a 400-foot building.
To calculate the time it takes for a ball to hit the ground when dropped from a certain height, we can use the equation:
h = (1/2)gt^2
Where:
h = height (in this case, 400 feet)
g = acceleration due to gravity (approximately 32.2 feet per second squared)
t = time
To solve for t, we need to rearrange the equation:
t^2 = (2h) / g
Now let's substitute the given values and solve for t:
t^2 = (2 * 400 ft) / 32.2 ft/s^2
t^2 = (800 ft) / 32.2 ft/s^2
t^2 = 24.84
Taking the square root of both sides, we find:
t ≈ √24.84
t ≈ 4.98 seconds
Therefore, it would take approximately 4.98 seconds for the ball to hit the ground when dropped from the top of a 400-foot building.