algebra

A recent study shows that the number of Australian homes with a computer doubles every 8 months. Assuming that the number is increasing continuously, at approximately what monthly rate must the number of Australian computer owners be increasing for this to be true?

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  1. n = N e^kt
    2 = 1 e^(k*8)
    ln 2 = 8 k = .693
    k = .0866

    dn/dt = kN e^kt
    at t = 0
    dn/dt = k N = .0866 N
    You must know how many there are now, N, to say how many per month are added.

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