In a group of 100 students, 60 are taking math and 12 are taking English, but no one is taking both. What is the probability that a randomly selected student from this group is taking either math or English?
Probability of either-or is found by adding the probability of the individual probabilities.
6/100 + 12/100 = ?
18
To find the probability that a randomly selected student is taking either math or English, we need to add the probabilities of these two events occurring separately.
First, let's find the probability that a student is taking math. We know that there are 60 students taking math out of a group of 100 students. Therefore, the probability of selecting a student taking math is 60/100 or 0.6.
Next, let's find the probability that a student is taking English. We're given that 12 students are taking English out of a group of 100 students. So, the probability of selecting a student taking English is 12/100 or 0.12.
Since no one is taking both math and English, we can add the probabilities of these two events to find the probability of selecting a student who is taking either math or English. Therefore:
Probability of math + Probability of English = 0.6 + 0.12 = 0.72
So, the probability that a randomly selected student from this group is taking either math or English is 0.72.