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"Two charges are 10 meters apart. The charge on the positive particle is 1.0 C and the negative charge is 10 Coulombs. Calculate the magnitude of the electrostatic force of attraction between these two charges."

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asked by william
  1. Use Coulomb's Law

    F = k Q1 Q2/R^2

    k = 8.99*10^9 N/m^2 C^2
    Q1 = 1 C
    Q2 = 10 C
    R = 10 m

    Your answer will be in Newtons. Never mind the minus sign on Q2. The force F will be an attraction since the charges are opposite.

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    posted by drwls

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