# ICS

I need help solving this question.

"Two charges are 10 meters apart. The charge on the positive particle is 1.0 C and the negative charge is 10 Coulombs. Calculate the magnitude of the electrostatic force of attraction between these two charges."

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1. Use Coulomb's Law

F = k Q1 Q2/R^2

k = 8.99*10^9 N/m^2 C^2
Q1 = 1 C
Q2 = 10 C
R = 10 m

Your answer will be in Newtons. Never mind the minus sign on Q2. The force F will be an attraction since the charges are opposite.

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posted by drwls

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