A 0.5537-g sample containing oxalic acid required 21.62 mL of 0.09377 M NaOH for titration. If the reaction is H2C2O4 + 2NaOH Na2C2O4 + 2H2O, calculate the % H2C2O4 in the sample.
Here is a worked example of a stoichiometry problem. Just follow the steps to obtain the theoretical yield.
Then %H2C2O4 = (mass H2C2O4/mass sample)*100 = (mass H2C2O4/0.5537)*100 = ?
Post your work if you get stuck. And keep the same screen name whether it be Polly, Meg, Tanya, or you name it.
16.11008228
0.18%
Well, it seems like someone threw some numbers at me, but I'll do my best to make sense of it like a clown at a math convention.
So, let's break it down. We have a sample weighing 0.5537 grams that required 21.62 mL of 0.09377 MNaOH for titration. According to the reaction equation H2C2O4 + 2NaOH ➔ Na2C2O4 + 2H2O, we can see that the ratio between H2C2O4 and NaOH is 1:2.
To calculate the % H2C2O4 in the sample, we need to determine how much H2C2O4 reacted with the NaOH. The number of moles of NaOH can be found using the formula:
moles of NaOH = concentration of NaOH (in M) x volume of NaOH used (in L)
So, moles of NaOH = 0.09377 M NaOH X (21.62 mL / 1000 mL/L) = ?
Ooops, looks like I'm missing some numbers here. My clown nose isn't quite up to the task of calculating without all the information. It seems like I need the molar mass of H2C2O4 and the moles of NaOH to proceed.
To calculate the percentage of oxalic acid (H2C2O4) in the sample, you need to first determine the number of moles of oxalic acid and the number of moles of NaOH used in the titration.
Step 1: Convert the given mass of the sample into moles.
Using the molar mass of oxalic acid (H2C2O4), we can convert the mass to moles:
Molar mass of H2C2O4 = (2 * 1.01 g/mol) + (2 * 12.01 g/mol) + (4 * 16.00 g/mol) = 90.03 g/mol
Number of moles of H2C2O4 = mass (g) / molar mass (g/mol) = 0.5537 g / 90.03 g/mol
Step 2: Calculate the number of moles of NaOH used.
To do this, we can use the balanced equation: H2C2O4 + 2NaOH → Na2C2O4 + 2H2O
From the equation, we can see that each mole of H2C2O4 reacts with 2 moles of NaOH.
Number of moles of NaOH = molarity (mol/L) * volume (L)
Given:
Molarity of NaOH (M1) = 0.09377 M
Volume of NaOH used (V1) = 21.62 mL = 21.62/1000 L
Number of moles of NaOH = 0.09377 M * 21.62/1000 L
Step 3: Calculate the percentage of H2C2O4 in the sample.
Percentage of H2C2O4 = (moles of H2C2O4 / total moles) * 100
Total moles = moles of H2C2O4 + moles of NaOH
Now you can plug in the values to calculate the percentage of H2C2O4.