Adult tickets for a play cost $15 and child tickets cost $6. If there were 33 people at a performance and the theater collected $360 from ticket sales, how many children attended the play?
14 children
15 children
16 children
18 children
If you can't figure this out with an equation, try process of elimination.
14 @ 6 = 84
19 @ 15 = 285
285 + 84 = 369
Nope, the first one is not correct.
If you need an equation.
let A = # adults
and C = # children
====================
number of attendees = 33; therefore,
A + C = 33
And cost of tickets was total of $360; therefore,
15*A + 6*C = 360
Solve the two equatins for A and C.
thank you i just didn't know how to set it up
To solve this problem, we can use a system of equations. Let's assign variables to the unknown values. Let's say x represents the number of adult tickets sold, and y represents the number of child tickets sold.
According to the problem, adult tickets cost $15, so the total revenue from adult tickets would be 15x. Similarly, child tickets cost $6, so the total revenue from child tickets would be 6y. The total revenue from ticket sales is given as $360.
Therefore, we can set up the following equation:
15x + 6y = 360
Additionally, the problem states that there were 33 people at the performance. Since we know that the number of adults (x) and children (y) must add up to 33, we can set up another equation:
x + y = 33
Now we have a system of equations:
15x + 6y = 360
x + y = 33
To solve this system, we can use substitution or elimination. Let's use elimination:
Multiply the second equation by 6 to make the coefficients of y the same in both equations:
6x + 6y = 198
Subtract this new equation from the first equation:
(15x + 6y) - (6x + 6y) = 360 - 198
Simplifying the equation, we get:
9x = 162
Divide both sides by 9:
x = 18
Now, substitute the value of x back into the second equation to find the value of y:
18 + y = 33
y = 33 - 18
y = 15
So, the number of children who attended the play is 15.
Therefore, the correct answer is 15 children attended the play.