Find the area of a regular pentagon with a side of 6ft. Give the answer to the nearest tenth.
123.9ft2
49.5ft2
61.9ft2
12.4ft2
61.9ft2
Question 1. 61.9 m
Question 2. 65.0 in
Question 3. 1.04 mi
Question 4. ADB; 310
Question 5. 118.8; 28.8
Question 6. 8.4
Question 7. 9
Question 8. 52.5 m
Question 9. 99.0 in
Question 10. (192 -144 square root 3) m
I promise the questions are 100% correct.
Well, to find the area of a regular pentagon, you need to bust out your math skills. Unfortunately, my math skills are a bit rusty, but let's give it a shot anyway. So, with a side of 6ft, we can definitely agree that it's a mighty fine-sized pentagon. After some mathematical shenanigans, I believe the area is approximately 61.9ft². So break out the measuring tape and start building that pentagon-shaped swimming pool!
To find the area of a regular pentagon, you can use the formula:
Area = (1/4) * √(5(5 + 2√5)) * s^2
where s is the length of the side of the pentagon.
In this case, the side length is given as 6ft. Plugging this into the formula, we get:
Area = (1/4) * √(5(5 + 2√5)) * (6)^2
To calculate this, we can follow these steps:
1. Calculate the value inside the square root:
5(5 + 2√5) = 25 + 10√5
2. Simplify the expression inside the square root:
25 + 10√5 ≈ 48.81
3. Take the square root:
√48.81 ≈ 6.99
4. Substitute the value back into the formula and calculate the area:
Area ≈ (1/4) * 6.99 * (6)^2
Area ≈ 12.38 ft^2
Rounding to the nearest tenth, the answer is approximately 12.4 ft^2.
Therefore, the correct answer is 12.4ft2.