Find the surface area of a sphere with a circumference of 40 ft. Round to the nearest tenth.

The Answer for “What is the surface area of a sphere with a circumference of 40ft? Round the answer to the nearest 10th” is 509.3ft^2

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To find the surface area of a sphere, we need to know either the radius or the diameter. In this case, we are given the circumference, which is the distance around the sphere.

The formula for the circumference of a sphere is:
C = 2πr

In this case, we are given the circumference of 40 ft. So we can solve the equation for the radius (r):
40 = 2πr

Dividing both sides by 2π gives:
40 / (2π) = r
r ≈ 6.37

Now that we have the radius, we can find the surface area of the sphere using the formula:
Surface Area = 4πr²

Substituting the value of r we found, we get:
Surface Area = 4π(6.37)²

Calculating this expression, we get:
Surface Area ≈ 508.9 ft²

Rounding to the nearest tenth, the surface area of the sphere is approximately 508.9 ft².

6.4ft

since

C = 2πr, r = C/2π

V = 4/3 π r^3 = 4/3 π (C/2π)^3 = C^3/6π^2 = 64000/6π^2