Find the current in the 10.0 resistor in the drawing (V1 = 20.0 V and R1 = 15.0 )..?

Not without the drawing

To find the current in the 10.0 Ω resistor, we can use Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across that resistor divided by its resistance.

In this case, we are given:

V1 = 20.0 V (the voltage across the entire circuit)
R1 = 15.0 Ω (the resistance of the entire circuit)

Now, we need to determine the voltage across the 10.0 Ω resistor.

Since the entire circuit has a voltage of 20.0 V, and there is a resistor with a resistance of 15.0 Ω, we can use the concept of voltage division to find the voltage across the 10.0 Ω resistor.

The voltage across the 10.0 Ω resistor can be calculated using the following formula:

V10 = V1 * (R10 / R1)

Where:
V10 is the voltage across the 10.0 Ω resistor
V1 is the voltage across the entire circuit (20.0 V)
R10 is the resistance of the 10.0 Ω resistor (given as 10.0 Ω)
R1 is the resistance of the entire circuit (15.0 Ω)

Plugging in the values, we get:

V10 = 20.0 V * (10.0 Ω / 15.0 Ω)

V10 = 13.333 V

Now that we have the voltage across the 10.0 Ω resistor, we can use Ohm's Law to find the current flowing through it.

The current (I) can be calculated using the formula:

I = V / R

Where:
I is the current flowing through the resistor
V is the voltage across the resistor (13.333 V)
R is the resistance of the resistor (10.0 Ω)

Plugging in the values, we get:

I = 13.333 V / 10.0 Ω

I ≈ 1.333 A

Therefore, the current flowing through the 10.0 Ω resistor is approximately 1.333 A.