What is the pH of a 2.8 M solution of HClO4?

To determine the pH of a solution of HClO4, you need to know the concentration of the solution and the dissociation constant (Ka) of HClO4.

1. Start by determining the dissociation constant (Ka) of HClO4, which is a strong acid. HClO4 dissociates completely in water, so its Ka can be assumed to be very large and can be considered as a strong acid that fully ionizes.

2. Next, calculate the concentration of H+ ions in the solution. Since HClO4 is a strong acid, it completely ionizes in water, so its concentration of H+ ions is equal to the concentration of HClO4 itself. Therefore, the concentration of H+ ions in the 2.8 M HClO4 solution is also 2.8 M.

3. Now, determine the pH using the equation for pH, which is defined as the negative logarithm (base 10) of the concentration of H+ ions in the solution. The equation is: pH = -log[H+].

In this case, the pH can be calculated as: pH = -log(2.8) = -0.447.

Therefore, the pH of the 2.8 M solution of HClO4 is approximately 0.447.