A hockey player makes a slap shot on a 2.0 kg stationary puck, exerting a 30N force for .16 seconds. A What impulse is given to the puck? B. With what velocity does the puck leave the stick?

To find the impulse given to the puck and the velocity at which it leaves the stick, we need to use the principles of impulse and momentum.

A. Impulse is defined as the change in momentum of an object. It is calculated by multiplying the force applied to an object by the time of application.

The formula for impulse is given as:

Impulse = Force × Time

In this case, the force applied to the puck is 30 N, and the time of application is 0.16 seconds. Plugging these values into the formula, we get:

Impulse = 30 N × 0.16 s
Impulse = 4.8 N·s

Therefore, the impulse given to the puck is 4.8 N·s.

B. To find the velocity at which the puck leaves the stick, we can use the principle of conservation of momentum. The momentum before the slap shot is equal to the momentum after the slap shot.

The formula for momentum is given as:

Momentum = Mass × Velocity

Initially, the puck is stationary, so its initial momentum is zero. After the slap shot, the puck gains a momentum equal to the impulse applied to it.

We know the impulse is 4.8 N·s, and the mass of the puck is 2.0 kg. Plugging these values into the formula, we can find the velocity of the puck:

4.8 N·s = 2.0 kg × Velocity

Simplifying the equation:

Velocity = 4.8 N·s / 2.0 kg
Velocity = 2.4 m/s

Therefore, the puck leaves the stick with a velocity of 2.4 m/s.