What mass of water must be added to 0.5 mol of glucose to make a solution of 25 percent by mass?The molar mass of glucose is 180 g/mol.
Well, let's crunch some numbers and embark on this water-adding adventure together!
To find out what mass of water is needed, we first need to determine the mass of the glucose. We can use the molar mass of glucose, which is 180 g/mol, and multiply it by 0.5 mol of glucose:
Mass of glucose = 0.5 mol × 180 g/mol = 90 g
Now, we know that the solution should be 25% glucose by mass, which means that the mass of glucose should make up 25% of the total mass of the solution.
Let's assume the total mass of the solution is M grams. Therefore, the mass of glucose in grams should be:
90 g = 0.25 × M
Solving for M, we have:
M = 90 g ÷ 0.25 = 360 g
So, the total mass of the solution would be 360 grams.
To find the mass of water needed, we subtract the mass of glucose from the total mass:
Mass of water = Total mass of solution - Mass of glucose
Mass of water = 360 g - 90 g = 270 g
Therefore, approximately 270 grams of water must be added to 0.5 mol of glucose to make a 25% solution by mass.
Now, hop aboard the water-adding train, and let's get this solution chuggin'!
To solve this problem, we first need to calculate the mass of 0.5 mol of glucose:
Mass of glucose = Number of moles of glucose × Molar mass of glucose
Mass of glucose = 0.5 mol × 180 g/mol
Mass of glucose = 90 g
Next, we can calculate the total mass of the solution using the mass percentage:
Mass percentage = Mass of solute / Mass of solution × 100
We can rearrange the equation to solve for the mass of the solution:
Mass of solution = Mass of solute / (Mass percentage / 100)
Substituting the given values:
Mass of solution = 90 g / (25 / 100)
Mass of solution = 90 g / 0.25
Mass of solution = 360 g
Finally, to find the mass of water to be added, we subtract the mass of glucose from the mass of the solution:
Mass of water = Mass of solution - Mass of glucose
Mass of water = 360 g - 90 g
Mass of water = 270 g
Therefore, 270 grams of water must be added to 0.5 mol of glucose to make a solution of 25 percent by mass.
To solve this problem, we need to determine the mass of the resulting solution when 25 percent of it is glucose.
Step 1: Calculate the mass of glucose:
Given that we have 0.5 mol of glucose and its molar mass is 180 g/mol, we can calculate the mass of glucose in grams:
Mass of glucose = Number of moles x Molar mass of glucose
Mass of glucose = 0.5 mol x 180 g/mol
Mass of glucose = 90 g
Step 2: Calculate the total mass of the solution:
We know that the resulting solution is 25 percent glucose by mass, which means that the remaining 75 percent is water. Let's assume the mass of the solution is W grams.
Mass of water = 75 percent of W
Mass of water = 0.75 x W
Step 3: Set up the equation:
We want the mass of glucose in the solution (90 g) to be 25 percent of the total mass of the solution (W). So we can set up an equation as follows:
90 g = 0.25 x W + 0.75 x W
Step 4: Solve for W:
Combine like terms:
90 g = 1 x W
Divide both sides by 1:
W = 90 g
So, the total mass of the solution is 90 grams.
Step 5: Calculate the mass of water:
We already know that the mass of glucose is 90 g, so the mass of water can be calculated as:
Mass of water = Total mass of solution - Mass of glucose
Mass of water = 90 g - 90 g
Mass of water = 0 g
Therefore, no additional mass of water needs to be added since the resulting solution is 100 percent glucose.
mass glucose/(g. glucose + g. H2O)x 100 = 25%
g glucose = mol x molar mass.