A hockey player makes a slap shot on a 2.0 kg stationary puck, exerting a 30N force for .16 seconds. A What impulse is given to the puck? B. With what velocity does the puck leave the stick?
To find the impulse given to the puck, we can use the formula:
Impulse = Force * Time
Given:
Force = 30 N
Time = 0.16 seconds
A. To find the impulse:
Impulse = Force * Time
Impulse = 30 N * 0.16 seconds
Impulse = 4.8 Newton-seconds (or kg·m/s)
So, the impulse given to the puck is 4.8 Newton-seconds (or kg·m/s).
B. To find the velocity at which the puck leaves the stick, we can use the principle of conservation of momentum. The impulse given to the puck is equal to the change in momentum of the puck.
Impulse = Change in momentum
The momentum of the puck before the slap shot is zero because it is stationary. Therefore, the change in momentum is equal to the final momentum after the slap shot.
Momentum = mass * velocity
Given:
Mass of the puck = 2.0 kg
Impulse = 4.8 Newton-seconds
Since Impulse = Change in momentum, we can write:
4.8 Newton-seconds = 2.0 kg * velocity
Solving for velocity:
velocity = 4.8 Newton-seconds / 2.0 kg
velocity = 2.4 m/s
So, the puck leaves the stick with a velocity of 2.4 m/s.