The difference of two numbers(the second minus the first) is 48. The second is 8 less than 5 times the first. What are the two numbers?
first one: x
second one: 5x-8
5x-8 - x = 48
etc
thank you so much
To solve this problem, we can use a system of equations. Let's call the first number "x" and the second number "y."
Based on the given information, we can create two equations:
1) "The difference of two numbers (the second minus the first) is 48."
This can be represented as: y - x = 48
Rearranging this equation, we get: y = x + 48
2) "The second number is 8 less than 5 times the first."
This can be represented as: y = 5x - 8
Now we have a system of two equations:
Equation 1: y = x + 48
Equation 2: y = 5x - 8
To find the values of x and y, we can substitute the value of y from Equation 1 into Equation 2.
Substituting y = x + 48 into Equation 2, we get:
x + 48 = 5x - 8
Simplifying the equation, we have:
48 + 8 = 5x - x
56 = 4x
Dividing both sides by 4:
x = 14
Now we can substitute x = 14 into Equation 1 to find y:
y = 14 + 48
y = 62
So, the two numbers are 14 and 62.