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The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?

(Note: this question refers to Newton’s equation for the force of gravity between two objects. How would that change if the radius of the earth or distance were increased by 100,000 meters. To help you answer this question, please review your textbook, chapter 3, Newton’s law of Gravitation section.)

F=(6.67 x10-11N.m2/kg2)(m1)(m2)
100,0002

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ThuyD

  1. g is inversely proportional to the square of the distance from the center of the earth.

    100 km above the earth's surface, g is reduced by a factor [6370/(6370+100)]^2 = 0.969
    That would make it 9.51 m/s^2

    6370 km is the radius of the earth.

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    drwls

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