The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the width of the rectangle.is it
1. 2 in.
2. 3 in.
3. 4 in.
4. 5 in.
let the width be x
then the length is 2x+8
x + x + 2x+8 + 2x+8 = 34
take it from there
To find the width of the rectangle, we can set up a system of equations based on the given information.
Let's denote the width of the rectangle as 'w' inches.
According to the problem, the length of the rectangle is 8 in. more than twice its width. So, the length can be expressed as "2w + 8" inches.
The perimeter of a rectangle is given by the formula:
Perimeter = 2(length) + 2(width)
Substituting the length and width values, we get:
34 = 2(2w + 8) + 2w
Simplifying the equation:
34 = 4w + 16 + 2w
Combine like terms:
34 = 6w + 16
Subtracting 16 from both sides:
18 = 6w
Dividing both sides by 6:
3 = w
Therefore, the width of the rectangle is 3 inches.
So, the correct answer is option 2.