The sum of two numbers is 76. The second is 8 more than 3 times the first. What are the two numbers?
x + (3x+8) = 76
Can you finish it
To solve this problem, let's assign variables to the two numbers. Let's call the first number "x" and the second number "y".
According to the problem, the sum of the two numbers is 76, so we can write the equation:
x + y = 76
It is also stated that the second number is 8 more than 3 times the first. In terms of equations, we can write:
y = 3x + 8
Now we have a system of two equations with two variables. We can solve this system using substitution or elimination method.
Let's solve it using substitution method:
From the second equation, we have y = 3x + 8. We can substitute this value of y into the first equation:
x + (3x + 8) = 76
Simplifying this equation, we get:
4x + 8 = 76
Subtracting 8 from both sides, we have:
4x = 68
Dividing both sides by 4, we get:
x = 17
Now that we have the value of x, we can substitute it back into the second equation to find y:
y = 3(17) + 8
y = 51 + 8
y = 59
Therefore, the two numbers are 17 and 59, respectively.