science equations

a boy standing n a high cliff dives into the ocean below and strikes the water after 2.5 s. what is the boy's velocity when he hits the water? deltav=gxt

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  1. As you have already stated,
    deltav=gxt

    That means the change in velocity (delta V) equals the acceleration of gravity (g = 9.8 m/s^2) times the time spent falling (2.5 s)

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