There are twenty balls in the bag. Twelve are white, six are orange and two are pink. When I draw a ball from the bag, I remove it. What is the probability that my first draw is a white ball and my second is not?

prob(white, non-white)

= (12/20)(8/19) = 24/95

To solve this problem, we need to calculate the probability of two events happening consecutively: the first event being drawing a white ball and the second event being not drawing a white ball.

First, let's find the probability of drawing a white ball on the first draw. We have a bag with a total of 20 balls, of which 12 are white. So, the probability of drawing a white ball initially is 12/20 (or simplified to 3/5).

After removing the first ball, we are left with 19 balls in the bag. The number of white balls now decreases to 11, while the total number of balls decreases to 19. Therefore, the probability of not drawing a white ball on the second draw is 1 - 11/19 (or simplified to 8/19).

To find the probability of both events occurring consecutively, we multiply the probabilities together. So, the probability of drawing a white ball on the first draw and not drawing a white ball on the second draw is (3/5) * (8/19) = 24/95.

Therefore, the probability that your first draw is a white ball and your second draw is not a white ball is 24/95.