Chemistry

Suppose 24.9 grams of copper (II) nitrate is dissolved in 200. milliliters of a 0.70 moles/liter aqueous solution of sodium chromate.

Calculate the final molarity of nitrate anion in the solution.

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  1. 24.9g/molar mass Cu(NO3)2 = mols Cu(NO3)2.
    There are two mols NO3^- for each mole Cu(NO3)2.
    Then M = mols/L soln = mols/0.200L = ?

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