the perimeter of some traffic sign must be 150 inches also its length is 15 inches longer than its width, find the dimensions of this sign
You don't say what shape your traffic sign is.
e.g.
a stop sign is a regular octogaon, yours can't be that
a yield sign is an equilateral triangle, not yours
etc.
however, since you mention only length and width, let's assume a rectangle.
2(w+(w+15)) = 150
4w + 30 = 150
w = 30
the sign is 30x45
To find the dimensions of the traffic sign, we can set up an equation using the given information.
Let's assume the width of the traffic sign is 'x' inches.
According to the given information, the length is 15 inches longer than the width, so the length would be (x + 15) inches.
The formula for the perimeter of a rectangle is: P = 2(length + width).
Substituting the given values, we have:
150 = 2((x + 15) + x)
Now, let's solve for 'x' to find the width of the traffic sign:
150 = 2(x + 15 + x)
150 = 2(2x + 15)
150 = 4x + 30
4x = 120
x = 30
Therefore, the width of the traffic sign is 30 inches.
To find the length, we substitute the value of 'x' back into the equation:
Length = x + 15 = 30 + 15 = 45 inches.
Hence, the dimensions of the traffic sign are 30 inches (width) and 45 inches (length).