How do you solve 1/6d + 13 = 20

How do you solve 3/5(s-8)=9

and 5+2c/4=14

1/6d + 13 = 20

1/6d =20-13
d/6 =7
d = 7*6
d = 42

3/5(s-8)=9
[3(s-8)]/5=9
3(s-8)=9*5
s-8 = 45/3
s =15 +8

s=23

the next one you try it

To solve the equation 1/6d + 13 = 20, you need to isolate the variable d on one side of the equation.

Here's the step-by-step process:

Step 1: Subtract 13 from both sides of the equation:
1/6d + 13 - 13 = 20 - 13
1/6d = 7

Step 2: To eliminate the fraction, multiply both sides of the equation by the reciprocal of 1/6, which is 6/1 or 6:
(1/6d) * 6 = 7 * 6
d = 42

Therefore, the solution to the equation 1/6d + 13= 20 is d = 42.