The radius of a chromium atom is 125 pm. How many chromium atoms would have to be laid side by side to span a distance of 1.62 mm?

Didn't I do one exactly like this for you (it wasn't Cr but some other element) yesterday. It's done the same way.

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TAYLOR, you're so stupid

To find out how many chromium atoms would have to be laid side by side to span a distance of 1.62 mm, we need to calculate the number of atoms that fit within that distance.

First, let's convert the given radius of the chromium atom from picometers (pm) to millimeters (mm). Since 1 mm is equal to 1,000,000 pm:

Radius of chromium atom = 125 pm * (1 mm / 1,000,000 pm)
Radius of chromium atom = 0.000125 mm

Now, let's calculate how many atoms would fit within the given distance of 1.62 mm:

Number of atoms = (Distance) / (Diameter of an atom)
Number of atoms = 1.62 mm / (2 * Radius of an atom)
Number of atoms = 1.62 mm / (2 * 0.000125 mm)

Therefore, the number of chromium atoms that would have to be laid side by side to span a distance of 1.62 mm is:

Number of atoms = 6480 atoms

So, 6480 chromium atoms would need to be laid side by side to span a distance of 1.62 mm.