Plan A cost 30 per year and 2.00 per game.
Plan B cost 75er year and 0.50 per game
Write a linear equation to find the cost of option A is equal to the cost of option B.
30 + 2x = 75 + .5x, where x = # of games per year.
To write a linear equation to find the cost of plan A equal to the cost of plan B, we need to set up an equation involving the variables that represent the costs of each plan.
Let's denote:
- Cost of plan A per year as A
- Cost of plan A per game as a
- Cost of plan B per year as B
- Cost of plan B per game as b
According to the given information, we have:
A = 30 (cost of plan A per year)
a = 2.00 (cost of plan A per game)
B = 75 (cost of plan B per year)
b = 0.50 (cost of plan B per game)
To find the equation where the cost of plan A is equal to the cost of plan B, we can set up the equation as:
A + a(x) = B + b(x)
Where x represents the number of games played.
In this scenario, we want to find the point where the cost of plan A and plan B are equal. This means the equation becomes:
30 + 2.00(x) = 75 + 0.50(x)
Simplifying this equation gives:
2.00x - 0.50x = 75 - 30
1.50x = 45
Dividing both sides by 1.50:
x = 30
Therefore, when x (number of games played) is equal to 30, the cost of option A is equal to the cost of option B.