If α, β, and γ are direction angles for a vector in three dimensions and cos α = 0.6 and cos β = 0.7, find cos γ
recall that
cos2α + cos2β + cos2γ = 1
.36 + .49 + cos2γ = 1
cos2γ = .15
cosγ = 0.38
cos2α + cos2β + cos2γ = 1
.36 + .49 + cos2γ = 1
cos2γ = .15
cosγ = 0.38