solve

3|x-8|=2x+7

i not get how to solve this the 3 infront of absolute value bracket confusing me.

This is not calculus. The 3 in front of |x-8| means 3 times |x-8|.

Solve these two cases separately:
If x>8
3x -24 = 2x + 7
x = 31

If x < 8
24 - 3x = 2x + 7
5x = 17
x = 17/5

3(x-8) = 2x+7 or 3(-x+8) = 2x+7

3x - 24 = 2x+7 OR -3x + 24 = 2x+7
x = 31 OR -5x = -17
x = 31 or x = 17/5

but 2x+7 ≥0 by definition of absolute value
x ≥ -7/2

both answers are correct
x = 31 or x = 17/5=3.4

thank you guys so much if you have time to spare can i post more questions? i not know when you guys go to sleep.

John Stewart comes on at 12:05, lol

btw this is actually pre-calculus publisher is absolute value publications

will you guys be here early in the morning?

morning where?