solve with an exact answer.
x^2 + 2x - 8
Start by factoring
(x+4)(x-2) = 0
The equation is true if either factor is zero.
x = +__ or -___
Can you show me the steps please???? to solve this equation.
I just did. The final answer is 2 or -4. Do you understand how to factor equations? That might be a topic worth reviewing.
If you wan to do it the hard way, you can also use the quadratic equation
x = [-b +/-sqrt(b^2-4ac)]/(2a)
Then substitute a = 1, b = 2 and c = -8
sqrt(b^2 -4ac) = sqrt36 = 6
x = (1/2)*[-2 +/-6]
= (1/2)(4 or -8)
= 2 or -4
Thank you so much and I definetly need to review how to factor equations<<<good night and sweet dreams>>>thank you for helping me
To solve the equation x^2 + 2x - 8 = 0 and find the exact solutions, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 2, and c = -8. So substituting these values into the quadratic formula, we get:
x = (-2 ± √(2^2 - 4(1)(-8))) / (2(1))
x = (-2 ± √(4 + 32)) / 2
x = (-2 ± √(36)) / 2
x = (-2 ± 6) / 2
Now, we have two possibilities: one with the plus sign and one with the minus sign.
Using the plus sign:
x = (-2 + 6) / 2
x = 4 / 2
x = 2
Using the minus sign:
x = (-2 - 6) / 2
x = -8 / 2
x = -4
So, the exact solutions to the equation x^2 + 2x - 8 = 0 are x = 2 and x = -4.