math
 👍
 👎
 👁

 👍
 👎
Respond to this Question
Similar Questions

Calculus Limits
Question: If lim(f(x)/x)=5 as x approaches 0, then lim(x^2(f(1/x^2))) as x approaches infinity is equal to (a) 5 (b) 5 (c) infinity (d) 1/5 (e) none of these The answer key says (a) 5. So this is what I know: Since

Algebra
Use the quadratic formula to solve the equation. Give exact answers: 2x^2 1 = 6x. The choices are: a) 3 + square root(7)/2, 3  square root(7)/2 b) 3 + square root(11)/2, 3  square root(11)/2 c) 3 + square root(7)/2, 3 

Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3

Calculus
A rectangle is bounded by the x axis and the semicircle = square root 25x^2. What length and width should the rectangle have so that its area is a maximum? When I worked the problem out(which is a bit detailed). I started with y

mathematics calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 5 if x ≤ 3 and 3 if x > 3 A.Lim f(x) x tends to 3+ B.Lim f(x) x tends to 3 C.Lim f(x) x tends to 3 D.Lim f(x) x tends

Calculus
Find the limit. lim 5x/(x^225) x>5 Here is the work I have so far: lim 5x/(x^225) = lim 5x/(x5)(x+5) x>5 x>5 lim (1/x+5) = lim 1/10 x>5 x>5 I just wanted to double check with someone and see if the answer is

Calculus Answer Confirming Not Sure Im Right Help?
Evaluate the lim a. lim x> 64 (cube root x4/x64) (∛x4)/(x64) > 0/0 so then let cube root x = u u4/u^364 u4/u^364 = u4/u4(u^2+4u+16) the u4 cancel each other out leaving lim x>64 = 1/u^2+4u+16 1/64^2+4(64)=16 oddly

calculus
Evaluate the limit or state that it does not exist. lim Root(6+x)Root(6x)/x x>0 i kept getting zero which ever way i tried to solve it.. help plz.

Math
Use graphing utility to graph function and estimate the limit. Use a table to reinforce your conclusion. Then find the limit by analytic methods. lim (sq root of (x+2)  sq root of 2) / x x>0 Thanks!

No one is helping me :/ ??
If y = 3 is a horizontal asymptote of a rational function, which must be true? lim x→ 3 f(x) = 0

Algebra
I think that the goal is to get rid of the 5th root in this case. I know that I have to make whatever is under or in the root in this case the number is X equal some number to the fifth power. I am supposed to use the rule

Calculus
uu) lim ln(1x) as x>1 yy) lim (√(6x)2)/(√(3x)1) as x> 2 zz) lim (1(1/2)arctanx) as x>∞ bbb) lim ln1x as x>1 If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it
You can view more similar questions or ask a new question.